`A,B` and `C` are three complexes of chromium(III) with the empirical formula `H_(12)O_(6)Cl_(3)Cr` All the three complexes not react with concentrated `H_(2)SO_(4)` whereas complexes `B` and `C` lose `6.75%` and `13.5%` of their original mass respectively, on treatment on treatment with conectrated `H_(2)SO_(4)` Identify `A,B` and `C` .

Explanation

`A=[Cr(H_(2)O)_(6)]Cl_(3)overset(H_(2)SO_(4))to NO reaction`
(therefour All `H_(2)O` molecules are present in co-ordination sphere)
`B = [CrCl(H_(2)O)]CI_(2)H_(2)Ooverset(H_(2)SO_(4))to` one mol e of `H_(2)O` is lost Molecular weight of complex = 266.5` % loss = `(18)/(266.5)xx100=6.75%`           `C=[CrCI_(2)(H_(2)O)_(4)]Cl_(2)2H_(2)O_(4)]Cl_(2)2H_(2)Ooverset(H_(2))to 2mol es` of `H_(2)O` is removedTherefour% loss in weight `= (2xx18)/(266.5)xx(100)=13.50%`