Each of these compounds `Pt(NH_(3))_(6)Cl_(4), Cr(NH_(3))_(6)Cl_(3), Co(NH_(3))_(4)Cl_(3)` and `K_(2)PtI_(6)`has been dissolved in water to make its 0,001 M solution. Rank them in order of their increasing conductivity.

Each of the compounmds Pt(NH_(3))_(6)Cl_(4), Cr(NH_(3))_(6)Cl_(3) and K_(2)PtCl_(6)Co(NH_(3))_(4)Cl_(3) were dissolved in water to make its 0.01 M solution. The correct order of their increasing conductivity in solution is

The name of the complex [Pt(NH_3)_6]Cl_4 is

[Cr(NH_(3))_(6)]^(3+)+6HCl to Cr^(3+)(aq)+6NH_(4)Cl

The name of the compound [Co(NH_(3))_(5) NO_2]Cl_2 will be

In solution, the complex, [Pt(NH_3)_6]Cl_4 gives

The correct name of |Pt(NH_(3))_(4)Cl_(2)||PtCl_(4)| is

The correct IUPAC name of [Pt(NH_(3))_(2)Cl_(4)] is

The two compounds [Co(SO_(4))(NH_(3))_(5)]Br and [Co(SO_(4))(NH_(3))_(5)]Cl represent:

The two compounds [Co(SO_(4))(NH_(3))_(5)]Br and [Co(SO_(4))(NH_(3))_(5)]Cl represent:

The IUPAC name of the complex [Pt (NH_3)_2Cl(NH_2CH_3)] Cl is