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Sulphide ions react with Na(2)[Fe(NO)(CN...

Sulphide ions react with `Na_(2)[Fe(NO)(CN)_(5)]` to form a purple coloured compound `Na_(4)[Fe(CN)_(5)(NOS)]` In the reaction, the oxidation state of iron is:

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Give the correct order of initials T of F for following statements. Use T if statements is true and F if it is false. I) Sulphide reacts with Na_(2)[Fe(CN)_(5)(NO)] to form a purple coloured compound Na_(4)[Fe(CN)_(5)(NOS)] . In the reaction, the oxidation state of iron changes. II) Pt(IV) compounds are relatively more stable than Ni(IV) compounds III) The welding of magnesium can be done in the atmosphere of Helium. IV) LiAlH_(4) on hydrolysis will give H_(2)

Sulphide ion reacts with [Fe(CN)_(5)NO] to form a purple coloured compound (X). In this reaction oxidation state of iron .

The compound K_(4)[Fe(CN)_(6)] is called

The complex Na_(2)[Fe(CN)_(5)NO] is called :

The oxidation state of Fe in Fe(CO)_(5) is

Oxidation number of Fe in violet coloured complex Na_(4)[Fe(CN)_(5)(NOS)] is :

Oxidation state of iron in Fe(CO)_(4) is

S-1 : [Cr(NH_(3))_(6)]^(3+) is a inner orbital complex with S-2: The complex formed by joining the CN ligands to Fe^(3+) ion has theoretical value fo 'spin only' magnetic moment equal to 1.73 B.M. S-3: Na_(2)S+Na_(2)[Fe(CN)_(5)NO]rarrNa_(4)[Fe(CN)_(5)NOS], In reactan and product the oxidation states of iron are same

A metal ion give chocolate coloured ppt with K_(4)[Fe(CN)_(6)] What is the oxidation state of that metal in its ion ?

In K_(4)[Fe(CN)_(6)],Fe is in the form of