Oleum is
Oleum is
A
a mixture conc. `H_(2)SO_(4)` and oil
B
sulphuric acid saturated with `SO_(3)`
C
a mixture of `H_(2)SO_(4)` and `HNO_(3)`
D
a mixture of `H_(2)SO_(4)` and HCl
Text Solution
Verified by Experts
The correct Answer is:
B
Similar Questions
Explore conceptually related problems
The percentage labelling (mixture of H_(2)SO_(4) and SO_(3)) refers to the total mass of pure H_(2)SO_(4) .The total amount of H_(2)SO_(4) found after adding calculated amount of water to 100 g oleum is the percentage labelling of oleum. Higher the percentage lebeling of oleum higher is the amount of free SO_(3) in the oleum sample. The percent free SO_(3) is an oleum is 20%. Label the sample of oleum in terms of percent H_(2) SO_(4) .
The percentage labelling (mixture of H_(2)SO_(4) and SO_(3)) refers to the total mass of pure H_(2)SO_(4) . The total amount of H_(2)SO_(4) found after adding calculated amount of water to 100 g oleum is the percentage labelling of oleum. Higher the percentage lebeling of oleum higher is the amount of free SO_(3) in the oleum sample. What is the amount of free SO_(3) in an oleum sample labelled as '118%'.
The percentage labelling (mixture of H_(2)SO_(4) and SO_(3)) refers to the total mass of pure H_(2)SO_(4) . The total amount of H_(2)SO_(4) found after adding calculated amount of water to 100 g oleum is the percentage labelling of oleum.Higher the percentage lebeling of oleum higher is the amount of free SO_(3) in the oleum sample. 100 g sample of '149%' oleum was taken and calculated amount of H_(2)O was added to make H_(2)SO_(4) . 500 mL solution of x MKOH solution is required to neutralize the solution. The value of x is.
0.5 gm of fuming H_(2)SO_(4) (Oleum) is diluted with water. This solution is completely neutralised by 26.7 ml of 0.4 M NaOH solution. Calculate the percentage of free SO_(3) in the given sample. Give your answer excluding the decimal places.
An oleum sample is labelled as 118%, Calculate Mass of H_(2)SO_(4) in 100 gm oleum sample
25 gm of an oleum sample contains 15 gm H_(2)SO_(4) . What is % labellling of this oleum sample-
Oleum acid is formed when sulphuric acid absorbs.
An oleum sample contains 10 g SO_(3) and 15 g H_(2) SO_(4) Answer the following questions on the basis of above information : % labelling of oleum sample is .
If all hydrogen atoms are present in its isotopic form of deuterium (._1H^(2)) in an oleum sample. Calculate percentage by mass of sulphur in 118 % of one such oleum sample (SO_(3)+D_(2)SO_(4) ).
Find the mass of Free SO_(3) present in 100gm, 109% oleum sample