When phosphine is passed through aqueous solution of copper sulphate, the product is

Options

A. `[Cu(OH)_(2)]`
B. `Cu_(3)P_(2)`
C. `[Cu(PH_(3))_(4)]^(2+)`
D. `[Cu(PH_(3))_(2)]^(2+)`

Answer

To solve the question of what product is formed when phosphine (PH₃) is passed through an aqueous solution of copper sulfate (CuSO₄), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
The reactants in this reaction are phosphine (PH₃) and copper sulfate (CuSO₄).

2. **Understand the Reaction**:
When phosphine is passed through an aqueous solution of copper sulfate, a chemical reaction occurs. Phosphine can react with copper ions (Cu²⁺) from copper sulfate.

3. **Write the Balanced Chemical Equation**:
The reaction can be represented as:
\[ 3 \text{CuSO}_4 + 2 \text{PH}_3 \rightarrow \text{Cu}_3\text{P}_2 + 3 \text{H}_2\text{SO}_4 \]
Here, the products formed are copper phosphide (Cu₃P₂) and sulfuric acid (H₂SO₄).

4. **Identify the Products**:
From the balanced equation, we can see that the main product formed is copper phosphide (Cu₃P₂).

5. **Conclusion**:
Therefore, when phosphine is passed through an aqueous solution of copper sulfate, the product is copper phosphide (Cu₃P₂).

### Final Answer:
The product formed is **Cu₃P₂** (copper phosphide).

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