Home
Class 12
CHEMISTRY
Calculate the standard free energy chang...

Calculate the standard free energy change in kJ for the reaction `Cu^(+) +I^(-) to CuI` Given:
`CuI + e to Cu+I^(-) E^(0)=-0.17V`
`Cu^(+)+e to Cu E^(0)=0.53V`

A

`-67.55`

B

`1315.1`

C

`1.78` V

D

`-1.75` V

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

Calculate the standard free enegry change for the reaction: Zn + Cu^(2+)(aq) rarr Cu+Zn^(2+) (aq), E^(Theta) = 1.20V

The standard free energy change of the reaction Cu^(2+)+Sn(s)rarrCu(s)+Sn^(2+) Given : E^(@)=0.48V ) is:

The Gibbs energy change (in J) for the given reaction at [Cu^(2+) ] = [Sn^(2+) ] = 1 M and 298 K is : Cu (s) + Sn^(2+) (aq) to Cu^(2+) (aq.) + Sn(s), (E_(Sn^(2+) // Sn)^(0) = -0.16 V E_(Cu^(2+) |Cu)^(0) = 0.34 V , Take F = 96500 C mol^(-1) )

Calculate the DeltaG^(@) and equilibrium constant of the reaction at 27^(@)C Mg+ Cu^(+2) hArr Mg^(+2) + Cu E_(Mg^(2+)//Mg)^(@) = -2.37V, E_(Cu^(2+)//Cu)^(@) = +0.34V

Calculate the equilibrium constant for the reaction at 298 K Zn(s)+Cu^(2+)(aq)harr Zn^(2+)(aq)+Cu(s) Given " " E_(Zn^(2+)//Zn)^(@)=-0.76 V and E_(Cu^(2+)//Cu)^(@)=+0.34 V

Calculate the equilibrium constant for the reaction Fe + CuSO_4 ⇌ FeSO_4 + Cu at 25°C. (Given E°(OP/Fe) = 0.5 V°, E°(OP/Cu) = -0.4 V)

Calculate the equilibrium constant for the reaction at 298K. Zn(s) +Cu^(2+)(aq) hArr Zn^(2+)(aq) +Cu(s) Given, E_(Zn^(2+)//Zn)^(@) =- 0.76V and E_(Cu^(2+)//Cu)^(@) = +0.34 V

Calculate the equilibrium constant for the reaction at 298K. Zn(s) +Cu^(2+)(aq) hArr Zn^(2+)(aq) +Cu(s) Given, E_(Zn^(2+)//Zn)^(@) =- 0.76V and E_(Cu^(2+)//Cu)^(@) = +0.34 V

Calculate E_("cell") at 25^(@)C for the reaction : Zn+Cu^(2+) (0.20M) to Zn^(2+) (0.50M)+Cu Given E^(Theta) (Zn^(2+)//Zn)= -0.76V, E^(Theta)(Cu^(2+)//Cu)=0.34V .

Calculate the maximum work that can be obtained from the decimolar Daniell cell at 25^(@)C . Given E^(c-)._((Zn^(2+)|Zn))=-0.76V and E^(c-)._((Cu^(2+)|Cu))=0.34V