If `A` and `B` are square matrices of the same order, explain, why in general `(A+B)^2!=A^2+2A B+B^2` (ii) `(A-B)^2!=A^2-2A B+B^2` (iii) `(A+B)(A-B)!=A^2-B^2` .

If A and B are square matrices of the same order such that A B=B A , then show that (A+B)^2=A^2+2A B+B^2

If A and B are square matrices of the same order such that A B=B A , then show that (A+B)^2=a^2+2A B+B^2

If A and B are square matrices of the same order such that A B=B A , then show that (A+B)^2=A^2+2A B+B^2 .

If A and B are square matrices of the same order then (A+B)^2=A^2+2AB+B^2 implies

Let A and B be square matrices of the same order. Does (A+B)^2=A^2+2A B+B^2 hold? If not, why?

If A and B are square matrices of the same order, then (A+B)(A-B) is equal to A^2-B^2 (b) A^2-B A-A B-B^2 (c) A^2-B^2+B A-A B (d) A^2-B A+B^2+A B

If A and B are square matrices of the same order such that AB=BA, then (A) (A-B)(A+B)=A^2-B^2 (B) (A+B)^2=A^2+2AB+B^2 (C) (A+B)^3=A^3A^2B+3AB^2+B^3 (D) (AB)^2=A^2B^2

If A and B are two square matrices of the same order then (A-B)^2 is (A) A^2-AB-BA+B^2 (B) A^2-2AB+B^2 (C) A^2-2BA+B^2 (D) A^2-B^2

If A and B are square matrices of the same order such that A=-B^(-1)AB then (A+3B)^(2) is equal to

Let A and B be square matrices of the order 3xx3 . Is (A B)^2=A^2B^2 ? Give reasons.