If P is a non-singular matrix, with (P^(...

If P is a non-singular matrix, with `(P^(-1))` in
terms of `'P',` then show that `adj (Q^(-1) BP^-1) = PAQ` . Given
that `(B) = A and abs(P) = abs(Q) = 1.`

Verified by Experts

The correct Answer is:

`(adj P)^(-1) or P `

Similar Questions

Explore conceptually related problems

If P is non-singular matrix, then value of adj(P^(-1)) in terms of P is (A) P/|P| (B) P|P| (C) P (D) none of these

P is a non-singular matrix and A, B are two matrices such that B=P^(-1) AP . The true statements among the following are

If adj B=A ,|P|=|Q|=1, then. adj(Q^(-1)B P^(-1)) is a. P Q b. Q A P c. P A Q d. P A^-1Q

Let p be a non singular matrix, and I + P + p^2 + ... + p^n = 0, then find p^-1 .

If adj B=A ,|P|=|Q|=1,t h e na d j(Q^(-1)B P^(-1)) is P Q b. Q A P c. P A Q d. P A^1Q

If tan(A+B)=p and tan(A-B)=q , then show that tan 2A=(p+q)/(1-pq)

If A, B are two n xx n non-singular matrices, then (1) AB is non-singular (2) AB is singular (3) (AB)^(-1)=A^(-1) B^(-1) (4) (AB)^(-1) does not exist

1/a, 1/b and 1/c are in A.P. Show that bc, ca, and ab are also in A.P.

If the (p+q)^(th) term of a G.P. is a and (p-q)^(th) term is b , determine its p^(th) term.

If a=x y^(p-1),\ b=x y^(q-1) and c=x y^(r-1) , prove that a^(q-r)b^(r-p)\ c^(p-q)=1