A be a square matrix of order 2 with |A|...

A be a square matrix of order `2` with `|A| ne 0` such that `|A+|A|adj(A)|=0`, where `adj(A)` is a adjoint of matrix `A`, then the value of `|A-|A|adj(A)|` is

A

1

B

2

C

3

D

4

Verified by Experts

The correct Answer is:

D

Similar Questions

Explore conceptually related problems

If A is a square matrix of order 2 and |A| = 8 then find the value of | adj(A)|

If A is a square matrix of order 3 such that |A|=5 , then |Adj(4A)|=

If |adj(A)|= 11 and A is a square matrix of order 2then find the value of |A|

A is a square matrix of order 3 and | A | = 7, write the value of |Adj A| is :

If M be a square matrix of order 3 such that |M|=2 , then |adj((M)/(2))| equals to :

If A is a square matrix of order 3 such that A (adj A) =[(-2,0,0),(0,-2,0),(0,0,-2)] , then |adj A| is equal to

If A is a square matrix of order 3 such that |A|=3 , then write the value of | adj A|

Let A be a square matrix of order 3 such that det. (A)=1/3 , then the value of det. ("adj. "A^(-1)) is

If A is a square matrix of order 3 such that det(A)=(1)/(sqrt(3)) then det(Adj(-2A^(-2))) is equal to

If A is a square matrix of order less than 4 such that |A-A^(T)| ne 0 and B= adj. (A), then adj. (B^(2)A^(-1) B^(-1) A) is