If the refractive index of glycerine = 1.48, water = 1.33, flint glass = 1.6, and diamond = 2.1, then, the speed of light is maximum in

Options

A. glycerine
B. water
C. flint glass
D. diamond

Answer

To determine in which medium the speed of light is maximum, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the relationship between speed of light and refractive index**:
The speed of light in a medium (V) is related to the speed of light in a vacuum (C) and the refractive index (μ) of that medium by the formula:
\[ V = \frac{C}{\mu} \]
Here, C is a constant (approximately \(3 \times 10^8\) m/s).

2. **Identify the refractive indices given**:
- Glycerine: μ = 1.48
- Water: μ = 1.33
- Flint Glass: μ = 1.6
- Diamond: μ = 2.1

3. **Determine the medium with the minimum refractive index**:
To find the medium where the speed of light is maximum, we need to find the minimum value of μ among the given mediums:
- Glycerine: 1.48
- Water: 1.33
- Flint Glass: 1.6
- Diamond: 2.1

The minimum refractive index is for water (1.33).

4. **Conclusion**:
Since the speed of light is inversely proportional to the refractive index, the speed of light will be maximum in the medium with the lowest refractive index. Thus, the speed of light is maximum in **water**.

### Final Answer:
The speed of light is maximum in **water**.

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