A ray of light is incident at an angle of 60° on a parallel side of a glass slab of thickness 0.1 m and refractive index 1.5. Calculate the lateral shift produced.

Explanation

`i = 60 ^(@)`
`t = 0.1 m`
`n = ( sin i )/( sin r)`
`1. 5 = (sin 60 ^(@))/( sin r )`
`sin r = (sin 60 ^(@))/( 1. 5) = 0. 5773`
`r = 35 ^(@) 16.`
Lateral shift `= (t sin (i -r ))/( cos r )`
`= ( 0.1 sin 24 ^(@) 44.)/( cos 36 ^(@) 16.)`
`= (0.1 xx 0. 41 84)/(0.81 64) = 0. 051 m`