The minimum deviation on a prism of refractive index `sqrt3` is equal to the angle of prism. Find the angle of the prism.

Explanation

To solve the problem, we need to find the angle of the prism (A) given that the minimum deviation (D) is equal to the angle of the prism and the refractive index (n) is equal to √3.

### Step-by-Step Solution:

1. **Understanding the Relationship**:
We know that for a prism, the relationship between the refractive index (n), the angle of the prism (A), and the minimum deviation (D) is given by:
\[
n = \frac{\sin\left(\frac{A + D}{2}\right)}{\sin\left(\frac{A}{2}\right)}
...