`(1+2/3+6/3^2+10/3^3+. . . + oo)^(log_(0.25)(1/3+1/3^2+1/3^3+. . . +oo))` is equal L and then find `L^2`

If the value of (1+(2)/(3)+(6)/(3^(2))+(10)/(3^(3))+...."upto "oo)^(log_((0.25))((1)/(3)+(1)/(3^(2))+(1)/(3^(3))+....."upto "oo) is l , then l^(2) is equal to _______.

The value of [(0.16)^(log_(2.5)(1/3+1/3^2+1/3^3+….+oo))]^(1/2) is

Value of (0.36)^(log_(0.25))((1)/(3)+(1)/(3^(2))+(1)/(3^(3))+....oo)=

Find the value of 3+1/(4+(1/(3+1/(4+1/(3+. . . oo))))) is equal to

The value of (0.16)^("log"_(0.25)((1)/(3) + (1)/(3^(2)) + (1)/(3^(3)) + …."to" oo)) , is

Value of y=(0.64)^((log_(2055))((1)/(3)+(1)/(3^(2))+(1)/(33)+...up rarr oo))

If x=3, then log_(4)(2log_(3)(1+log_(2)(1+3log_(3)x))) is equal to