Henry's law constant for `CO_2` in water is 0.835x2x`10^3`bar.How many millimoles of `CO_2` would dissolve in 0.9L water? Assume `CO_2` gas exerts a partial pressure of 0.853bar

If N_(2) gas is bubbled through water at 293 K , how many millimoles of N_(2) gas would dissolve in 1 L of water. Assume that N_(2) exerts a partial pressure of 0.987 bar. Given that Henry law constant for N_(2) at 293 K is 76.48 kbar.

Henry's law constant of CO_2 in water at 298K is 5/3K bar. IF pressure of CO_2 is 0.01 bar, find its mole fraction.

Henry's law constant for CO_(2) in water is 2.5xx10^(8)Pa at 298K . Calculate mmole of CO_(2) dissolved in 14g water at 2.5atm pressure at 298K . [Take 1atm=10^(5)N//m^(2) or Pa ]

henry's law constant for CO_(2) in water is 2.5xx10^(8) Pa at 298K calcualte mmole of CO_(2) dissolbed in 144 g water at 2.5 atm pressure at 298K. [take 1 atm =10^(6)(N)/(m^(2)) or Pa]

Henry's law constant for CO_(2) in water is 1.67xx10^(8) Pa at 298 K . Calculate the quantity of CO_(2) in 500mL of soda water when packed under 2.5atm CO_(2) pressure at 298 K .