A potential difference is applied across a wire of length 1 m and resistance `10 Omega` , such that the current through it is 1 A. The electric field inside the wire is __________N/C.

Explanation

To find the electric field inside the wire, we can follow these steps:

### Step 1: Understand the relationship between potential difference, current, resistance, and electric field.
The electric field (E) in a conductor can be defined using the formula:
\[ E = \frac{V}{L} \]
where \( V \) is the potential difference across the conductor and \( L \) is the length of the conductor.

### Step 2: Use Ohm's Law to find the potential difference (V).
According to Ohm's Law:
\[ V = I \times R \]
where:
- \( I \) is the current (1 A)
- \( R \) is the resistance (10 Ω)

Substituting the values:
\[ V = 1 \, \text{A} \times 10 \, \Omega = 10 \, \text{V} \]

### Step 3: Calculate the electric field (E).
Now that we have the potential difference, we can substitute \( V \) and \( L \) into the electric field formula:
\[ E = \frac{V}{L} = \frac{10 \, \text{V}}{1 \, \text{m}} = 10 \, \text{N/C} \]

### Final Answer:
The electric field inside the wire is \( 10 \, \text{N/C} \).

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