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Two liquids A and B have PA^(@)" and PB^...

Two liquids A and B have `P_A^(@)" and P_B^(@)` in the ratio of 1 : 3 and the ratio of number of moles of A and B in liquid phese are 1 : 3 then mole fraction of 'A' in vapour phase in equilibrium with the solution is equal to :

A

`0.1`

B

`0.2`

C

`0.5`

D

`1.0`

Text Solution

Verified by Experts

The correct Answer is:
A
`x_(A) =(1)/(1+3) rArr (1)/(4), x_(B) =(3)/(4)`,
`(y_(A))/(y_(B))=(P_(A)^(@))/(P_(B)^(@))xx(x_(A))/(x_(B))`
`(y_(A))/((1-y_(A)))=(1)/(3)xx(1)/(3) rArr (1)/(9)" or "y_(A) =(1)/(10)`
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