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For the reaction 2N(2) O(5) (g) overset(...

For the reaction `2N_(2) O_(5) (g) overset(k)rarr 4NO_(2) (g) + O_(2) (g)` having rate law. Rate =`k [N_(2)O_(5)]=R_(1)`
Select correct statement.

A

Rate constant of the reaction would be 0.25L `"mole"^(-1) sec^(-1)`

B

Rate of disappearance of `N_(2)O_(5) (g) = R_(1)`

C

Rate of formation of `NO_(2) (g)= 4R_(1)`

D

Arrhenius constant for the reaction is `10^(6)` mole `L^(-1) "min"^(-1)`

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To solve the question regarding the reaction \[ 2N_2O_5 (g) \overset{k}{\rightarrow} 4NO_2 (g) + O_2 (g) \] with the rate law \[ \text{Rate} = k [N_2O_5] = R_1, \] we need to analyze the statements provided and determine which one is correct. ### Step-by-Step Solution: 1. **Understanding the Rate Law**: The rate law indicates that the rate of the reaction depends on the concentration of \(N_2O_5\). The rate constant \(k\) is a proportionality constant that relates the rate of the reaction to the concentration of the reactants. 2. **Identifying the Order of the Reaction**: Since the rate law is given as \( \text{Rate} = k [N_2O_5] \), this indicates that the reaction is first order with respect to \(N_2O_5\). The overall order of the reaction is 1. 3. **Rate of Disappearance of \(N_2O_5\)**: The rate of disappearance of a reactant is given by the negative change in concentration over time. For \(N_2O_5\), this can be expressed as: \[ -\frac{d[N_2O_5]}{dt} = R_1 \] Thus, the rate of disappearance of \(N_2O_5\) is equal to \(R_1\) but with a negative sign, indicating a decrease in concentration. 4. **Rate of Formation of \(NO_2\)**: The stoichiometry of the reaction shows that for every 2 moles of \(N_2O_5\) that react, 4 moles of \(NO_2\) are formed. Therefore, the rate of formation of \(NO_2\) can be expressed as: \[ \frac{d[NO_2]}{dt} = \frac{4}{2} \cdot R_1 = 2R_1 \] However, since we need to account for the stoichiometric coefficients correctly, we find: \[ \frac{d[NO_2]}{dt} = 4R_1 \] This means that the rate of formation of \(NO_2\) is indeed \(4R_1\). 5. **Evaluating the Arrhenius Constant**: The Arrhenius constant (or pre-exponential factor) is not provided in the problem statement, and without specific data, we cannot determine its value. Thus, any statement regarding the Arrhenius constant would be incorrect. ### Conclusion: Based on the analysis, the correct statement is that the rate of formation of \(NO_2\) is equal to \(4R_1\).

To solve the question regarding the reaction \[ 2N_2O_5 (g) \overset{k}{\rightarrow} 4NO_2 (g) + O_2 (g) \] with the rate law ...
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