Home
Class 12
CHEMISTRY
The radius of Ag^(+) ion is 126 pm and t...

The radius of `Ag^(+)` ion is 126 pm and that of `I^(-)`ion is 216 pm. The coordination number of `Ag^(+)` ion is:

Text Solution

Verified by Experts

The correct Answer is:
6
`(r_(+))/(r_(-))=(126)/(216)=0.58`, octahedral voids so C.N. =6
Promotional Banner

Similar Questions

Explore conceptually related problems

Early crystallographers had trouble solving the structures of inorganic solids using X-ray diffraction because some of the mathematical tools for analyzing the data had not yet been developed. Once a trial structure was proposed, it was relatively easy to calculate the diffraction pattern, but it was difficult to go the other way (from the diffraction pattern to the structure) if nothing was known a priori about the arrangement of atoms in the unit cell. It was important to develop some guidelines for guessing the coordination numbers and bonding geometries of atoms in crystals. The first such rules were proposed by Linus Pauling, who considered how one might pack together oppositely charged spheres of different radii. Pauling proposed from geometric considerations that the quality of the "fit" depended on the radius ratio of the anion and the cation. If the anion is considered as the packing atom in the crystal, then the smaller cation fills interstitial sites ("holes"). Cations will find arrangements in which they can contact the largest number of anions. If the cation can touch all of its nearest neighbour anions then the fit is good. If the cation is too small for a given site, that coordination number will be unstable and it will prefer a lower coordination structure. The table below gives the ranges of cation/anion radius ratios that give the best fit for a given coordination geometry. The radius of Ag^+ ion is 126pm and of I^- ion is 216pm. The coordination number of Ag^+ ion is:

The radius of the Na^(+) is 95 pm and that of CI ion is 181 pm Predict the coordination number of Na^(+) ?

The radius of Na(+) is 95 pm and that of CI^(-) ions is 181 pm. Predict whethr the coordination number of Na^(+) is 6 or4.

The radius of cation is 100 pm and that of anion is 188 pm, then the coordination number of cation is __________.

The radius of Cs^(+) ion is 160pm while the radius of Cl^(-) ion is 181pm . Suggest the co - ordination of cesium in CsCl .