lim(n rarr oo)n sin\ (2 pi)/(3n)*cos\ (2...

`lim_(n rarr oo)n sin\ (2 pi)/(3n)*cos\ (2 pi)/(3n)`

A

`(2pi)/(3)`

B

`(pi)/(6)`

C

`( pi)/(3)`

D

`1`

Verified by Experts

The correct Answer is:

A

`lim_(n to oo) ([n"sin"(2pi)/(3n)])/(((2pi)/(3n)))*("cos" (2pi)/(3n))xx((2n)/(3n))=lim_(n to oo)n*cos((2n)/(3n))xx(2pi)/(3n)=(2pi)/(3)`

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