Acoording to x/m = `Kp^(1//n)`, when pressure increases 2 times than concentration becomes 64 times. Find value of n

For a reaction,\(A \rightarrow products\), rate increases x times when concentration of 'A' increases y' times, then order of reaction is

x/m prop Kp^(1/n) . Find the value of n

If concentration of reactant is increased by 2 times then K becomes :-

For a reaction R to P, the rate becomes 2 times when the concentration of the reactant P is increased 4 times. What is the order of reaction ?

For the reaction 2" X"to"X"_(2) , the rate reaction becomes 27 times when the concentration of X is increased three times. What is the order of the reaction ?

Conisder a reaction X + Y rarr Products. If the initial concentration of X increased to four times of its original value, keeping the concentration of Y constant, the rate of reaction increases four-fold. When the concentration of both X and Y becomes four times their original values the rate of reaction becomes 16 times its original values. The observed rate law is

For the reaction AtoB , the rate of reaction becomes three times when the concentration of A is increased by nine times. What is the order of reaction ?

For a reaction A to B, the rate of reaction becomes twenty seven times when the concentration of A is increased three times. What is the order of the reaction?