`PCl_5 to PCl_3 + Cl_2` `K_c = 1.844`
If 3 moles of `PCl_5` are taken in 1L vessel. Find equilibrium concentration of `PCl_5`

PCl_(5) hArr PCl_(3) + Cl_(3) " "K_(c)= 1.844 3.0 moles of PCl_(5) is introduced in a 1 L closed reaction vessel at 380 K. The number of moles of PCl_(5) at equilibrium is ________ xx 10^(-3) . (Round off to the Nearest Integer)

For the reaction PCl_(5)hArr PCl_(3)+Cl_(2) in gaseous phase, K_(c)=4 . In a 2L flask, there are 2 moles each of PCl_(3) and Cl_(2) and 0.5 mole of PCl_(5) . Equilibrium concentration of PCl_(5) is

Three moles of PCl_(5) , three moles of PCl_(3) and two moles of Cl_(2) are taken in a closed vessel. If at equilibium, the vessel has 1.5 moles of PCl_(5) the number of moles of PCl_(3) present in it is

In the reaction, PCl_(5)hArrPCl_(3)+Cl_(2) , the amounts of PCl_(5) , PCl_(3) and Cl_(2) , 2 moles each at equilibrium and the total pressure is 3 atm . Find the equilibrium constant K_(p) .