Find the value of `(veca+vecb)xx[vecaxx((veca-vecb)xxvecb)]`

If veca=hati+hatj+hatk , vecb=2hati+hatj-hatk and vecc=4hati+3hatj+hatk then value of ((veca+vecb)xx(veca -(veca-vecb)xxvecb)))xxvecc is

Let veca and vecb be unit vectors such that |veca+vecb|=sqrt3 . Then find the value of (2veca+5vecb).(3veca+vecb+vecaxxvecb)

The value of veca.(vecb+vecc)xx(veca+vecb+vecc) , is

If veca, vecb and vecc are three non - zero and non - coplanar vectors such that [(veca,vecb,vecc)]=4 , then the value of (veca+3vecb-vecc).((veca-vecb)xx(veca-2vecb-3vecc)) equal to

the value of (vecA+vecB)xx(vecA-vecB) is

If [ veca vecbvecc]=2 , then find the value of [(veca+2vecb-vecc) (veca - vecb) (veca - vecb-vecc)]

If [ veca vecbvecc]=2 , then find the value of [(veca+2vecb-vecc) (veca - vecb) (veca - vecb-vecc)]

If |veca|=2, |vecb|=5 and veca*vecb=0 , then veca xx (vecaxx(vecaxx(vecaxx(vecaxx(veca xx vecb))))) is equal to :

Prove that (veca+3vecb)xx(veca+vecb)+(3veca-5vecb)xx(veca-vecb)=0

If veca and vecb are non-zero, non parallel vectors, then the value of |veca + vecb+veca xx vecb|^(2) +|veca + vecb-veca xx vecb|^(2) equals