A compound forms hexagonal close packed structure. What is· the total number of voids in 0.5 mol of it? How many .of these are tetrahedral voids ?

Explanation

Number of atoms in the 0.5 mol close-packed structure
`=0.5xx6.22xx10^(23)=3.011xx10^(23)`
Number of octahedral voids = I x number of atoms in close packed structure
`=1xx3.011xx10^(23)=3.011xx10^(23)`
Number of tetrahedral voids = 2 x numt>er of atoms in closepacked structure
`=2xx3.011xx10^(23)=3.011xx10^(23)`
Total number of voids `=3.011xx10^(23)+6.022xx10^(23)=9.033xx10^(23)`