Silver metal crystallise with a face centred cubic .lattice. The length of unit cell is found to be `4.077 xx 10^(-8) cm`. Calculate the atomic radius and density of silver (Atomic mass of Ag= 108 u, `NA= 6.02 x 10^(23) mol^(-1)`.

Explanation

For fee z = 4
and `r=a/(2sqrt2)a=4.077xx10^(-8)cm=(4.077xx10^(-8))/(2sqrt2)=1.44xx10^(-8)cm`
Now `d=(ZxxM)/(a^3xxN_A)` here Z=4
`M=108a=4.077xx10^(-8)`
So `d=(4xx108)/((4.077xx10^(-1))^3)xx6.02xx10^(23)=10.5gm//cm^3`