Tungsten has body centred cubic lattice. Each edge of the unit is 316 pm and density of the metal is `19.35"g cm"^(-3)`. How many atoms are present in 50 g of the metal ?

Explanation

Edge length (a)= 316 pm
Volume `(a^3)=(316xx10^(-10))^3=31554496xx10^(-30)cm^(-3)`
For bcc Z =2
`d=(ZxxM)/(a^3xx"no. of atoms")`
Number of atoms `=(ZxxM)/(a^3xxd)=(2xx50)/(31554496xx10^(30)xx19.35)=(100xx10^(30)xx10^(-7))/(61.0579498)=1.64xx10^(23)`