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A aqueous solution contains 10 moles of ...

A aqueous solution contains 10 moles of sucrose in 1 kg of solvent. calculate the molality of solution.

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300 g of 25% solution contains solute = 75 g
400 g of 40% solution contains solute = 160 g
Total solute = 160 + 75 = 235 g
Total solution = 300 + 400 = 700 g
Percentage of first solute in the final solution = `235/(700)xx100=33.5%`
Percentage of second solute in the final solution = `100-33.5=66.5%`
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OMEGA PUBLICATION-SOLUTIONS-Multiple Choice Questions
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  14. Which of the following is a colligative property?

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