How many gram equivalents of H2SO4 are present in 200 ml of N/10 H2SO4 solution ?

Explanation

`"Molarity (M)"=("Mass od solute/ molar mass")/("Volume of solution in litre")`
M = 0.15 M = 0.15 mol `L^(-1)`
Molar mass of solute = 122 g `mol^(-1)`
Volume of solution = 250 mL - 0.25 L
`(0.15"mol l"^(-1))=("Mass of solute")/((122"g mol"^(-1))xx(0.25L))`
Mass of solute = `0.15xx1.22xx0.25=4.575` g