1.0 gram of a non-volatile solute was dissolved in 100 gram of acetone (molecular mass = 58) at 298 K. The vapour pressure of solution was found to be 192.5 mm of Hg. Calculate the molecular mass of solute. The vapour pressure of pure acetone at 298 K is 195 mm of Hg.

The vapour pressure of a 5% aqueous solution of a non-volatile organic substances at 373K is 745 mm. calculate the molar mass of the solute. (Vapour pressure of water at 373K=760mm Hg).

If the vapor pressure of a dilute aqueous solution of glucose is 750 mm of Hg at 373 K , then molality of solute is

100 g of liquid A (molar mass 140 g mol^(-1) was dissolved in 1000 g of liquid B (molar mass 180 g mol^(-1)) . The vapour pressure of pure liquid B was found to be 500 torr. Calculate the vapour pressure of pure liquid A and its vapour pressure in the solution if the total vapour pressure of the solution is 475 Torr.

The mass of a non-volatile solute of molar mass 40gmol^-1 that should be dissolved in 114 g of octane to lower its vapour pressure by 20% is

What mass of a non-volatile solute, urea (NH_2CONH_2) need to be dissolved in 100 g of water in order to decrease the vapour pressure of water by 25%? What is the molality of the solution?

6.0 g of urea (molecules mass = 60)was dissolved in 9.9 moles of water. If the vspour presssure of pure water is P^(@) , the vapour pressure of solution is :

Calculate the vapour pressure of an aqueous solution containing 5% by mass of urea (NH_2CON_2) at 298K. The vapour pressure of water at 298K is 23.75 mm Hg.

The vapour pressure of an aqueous solution of glucose is 750 mm of mercury at 100^@ C . Mole fraction of solute will be

18 g of a compound is dissolved in 10 kg of water so that the resulting solution freezes at - 8^(@) C . If K_(f) for water = 1 . 86 K/m . Calculate the molecular mass of the compound

Vapour pressure of water at 20^C is 17.5 mm of Hg and lowering of vapour pressure of a sugar soluton is 0.061 mm of Hg. Calculate relative lowering of vapour pressure?