A solution containing 12.5 g of a non- electrolyte substance in 175 g of water gave boiling point elevation of 0.70 K. Calculate the molar mass of the substance (`K_b` for water = 0.52 K kg `mol^(-)`).

Explanation

Give that
`DeltaT_(b)=0.70K,W_(A)=175g,`
`K_(b)=5.2"K kg mol"^(-1)` `W_(B)=12.5g`
Formula used
`M_(B)=(K_(b)xxW_(B)xx1000)/(DeltaT_(b)xxW_(A))` `M_(B)=(0.52xx12.5xx1000)/(0.70xx175)=53.06g`