How many grams of ethylene glycol (molar mass = 62) should be added to 10 kg of water, so that the resulting solution freezes at `-10^(@)C` (`K_(f)` for water = 1.86 K `"mol^(-1)`).

Explanation

`DeltaT_(f)=T_(f)^(@)-T_(f),DeltaT_(f)=O-(-10),DeltaT_(f)=10^(@)C,K_(f)=1.86"K Kg mol"^(-1)`
Mass of solvent = 10 Kg
`DeltaT_(f)=K_(f)m`
`10=K_(f)xxW_(B)/(M_(B))xx1/(10)rArrW_(B)=(10xx62xx10)/(1.86)`
`W_(B)=3333.3grArrW_(B)=3.33kg`