An aqueous solution freezes at 1.186^(@)...

An aqueous solution freezes at `1.186^(@)C` (`K_(f)=1.86,K_(b)=0.512`). What is the elevation in boiling point?

0.186

0.512

0.86

0.0512

Text Solution

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The correct Answer is:

`DeltaT_(f)=K_(f)xxmandDeltaT_(b)=K_(b)xxmor(DeltaT_(f))/(DeltaT_(b))=K_(f)/(K_(b))`
`DeltaT_(b)=0.186/(1.86)xx0.512=0.0512`

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