Calculate the potential of hydrogen electrode income with a solution whose pH is 10.

Explanation

For Hydrogen electrode, `H^(+)+e^(Theta)rarr(1)/(2)H_(2)`
Applying Nearnst equation
`E_((H^(+)//(1)/(2)H_(2)))=E_((H^(+)//(1)/(2)H_(2)))^(@)-(0.0591)/(n)log""(1)/([H^(+)])=0-(0.0591)/(1)log""(1)/((10^(-10)))[pH=10,[H^(+)]=10^(-10)M]`
`=0-(0.0591)/(1)xx10log10=-0.591V`.