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Calculate DeltaG^(@) and equilibrium con...

Calculate `DeltaG^(@)` and equilibrium constant for the cell reaction,
`Cl_(2)+2l^(-) hArr 2Cl^(-)+I_(2)`
Given that: `E^(@)(Cl_(2),Cl^(-))=1*36V,E^(@)(l_(2),l^(-))=0*536V`

Text Solution

Verified by Experts

We know that
`E_("cell")^(@)=E_("Cathode")^(@)-E_("anode")^(@)`
`=1.36-0.536=0.824`
Using the relation `DeltaG^(@)=-nFE_("Cell")^(@)`
`=-2xx96500xx0.824=159032J//mol^(-1)=159.03KJ`
`DeltaG^(@)=-2.303RTlogK_(c)159032=-2.303xx8.314xx298xxlogK_(c)`
`logK_(c)=(-159032)/(2.303xx8.314xx298)=(-159032)/(-5705.8)`
`K_(c)="Antilog "27.8719 ,K_(c)=0.7445xx10^(28)=7.445xx10^(27),K_(c)=8.555xx10^(27)`
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