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Calculate the cell e.m.f. and DeltaG for...

Calculate the cell e.m.f. and `DeltaG` for the cell reaction at `25^(@)C` for the cell:
`Zn_((s))|Zn^(2+)(0.004M)||Cd^(2+)(0.2M)|Cd_((s))`
`E^(@)` values at `25^(@)C,Zn^(2+)//Zn=-0.763V`
`Cd^(+2)//Cd=-0.403V`
`F=96,500,R=8.314JK^(-1)mo"le"^(-1)`.

Text Solution

Verified by Experts

`Zn(s)//Zn^(2+)(0.004)||Cd^(2+)(0.2)//Cd(s)`
`E_("cell")=E_("cell")^(@)-(0.059)/(n)log""([Zn^(2+)])/([Cd^(2+)])`
`E_("cell")=-0.403-(-0.763)-(0.059)/(2)log""(0.004)/(0.2)`
`E_("cell")=0.36-(0.059)/(2)log(2xx10^(-2))`
`E_("cell")=0.36-(0.059)/(2)(-1.699)=0.36+0.1`
`E_("cell")=0.46`
`DeltaG=-nEF`
`=-2xx0.46xx96500`
`88780J`
`=88.78kJ`
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