The resistance of a 0.5 M solution of an electrolyte in a conductivity 'cell was found to be 25 ohm. Calculate the molar conductivity of the solution, if the electrodes in the cell are 1.6 cm apart and have an area of `3*2cm^(2)`.

Explanation

Resistance (R ) = 25 W
Normality (C ) = 0.5 N
Length (l) = 1.6 cm
Area (a) = `3.2cm^(2)`
`wedge_(eq)=(kxx1000)/(N)`
`K=(1)/(R )xx(l)/(a)=(1)/(25)xx(1.6)/(3.2)`
`K=0.02`
`wedge_(eq)=(0.02xx1000)/(0.5)=4052Omega^(-1)cm^(2)("g eq.")^(-1)`.