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The number of d-electrons in [Cr(H2O)6]^...

The number of d-electrons in `[Cr(H_2O)_6]^(3+)` (at. No. of Cr = 24 ) is

A

2

B

3

C

4

D

5

Text Solution

Verified by Experts

The correct Answer is:
B
Oxidation state of Cr in `[Cr(H_2O)_6]^(3+)` is +3.
`:. Cr^(+3)` have configuration `[Ar]^18 3d^3 45^@`. So have three d- electrons.
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