If ten volume of dihydrogen gas react with five volume of dioxygen gas how many volume of water vapour would be produced?

Explanation

We have given equation
`{:(2H_(2)(g),+,O_(2)(g),rarr,2H_(2)(g)),(2V,,IV,,2V):}`
According to Gay Lussac.s law of gaseous volumes 2V of hydrogen react with 1V of `o_(2)` to produce 2V of `H_(2)O` vapour
`therefore` 10V of dihydrogen on reaction with 5V of dioxygen will produce 10V of `H_(2)O` vapour.