Calculate the amount of carbon dioxide that would be produced when 1 mole of carbon is burnt in 16 g dioxygen.

Explanation

The chemical equation is
`{:(C(s),+,O_(2)(g),rarr,CO_(2)(g)),(1"mol",,1"mol",,1"mol"),(,,32g,,44g):}`
1 mole of carbon requires 32g dioxygen from the reaction. But we have only 16g dioxygen. Hence dioxygen is the limiting reagent. So the amount of `CO_(2)` produced by 16g dioxygen is