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Calculate the percentage composition of `Ca(NO_(3))_(2)`

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We are given a compound `Ca(NO_(3))_(2)`
Molecular mass of `Ca(NO_(3))_(2)=` Atomic mass of `Ca+2 xx` atomic mass of `N=6 xx` atomic mass of oxygen `=40 + 2 xx 14+6 xx 16= 164u`
We are to calculate the percentage composition of Ca, N, O
Percentage of Calcium (Ca)= `("Mass of Ca")/("Molecular mass of " Ca(NO_(3))_(2))xx 100= (40)/(164) xx 10 = 24.39%`
Percentage of Nitrogen (N) `= (2 xx "Mass of N")/("Molecular mass of" Ca(NO_(3))_(2)) xx 100= (28)/(164) xx 100= 17.07%`
Percentage of Oxygen `(O)= (6 xx "Mass of O")/("Molecular mass of "Ca(NO_(3))_(2)) xx 100 = (96)/(164) xx 100= 58.54%`
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