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An organic substance containing carbon, ...

An organic substance containing carbon, hydrogen and oxygen gave following percentages, C= 40.68%, `H_(2)`= 5.085% and `O_(2)`= 54.22%. The vapour density of the compound is 59. Calculate the molecular formula of the compound.

Text Solution

Verified by Experts

We are given that
(i) Percentage composition of C= 40.68
Percentage composition of `H_(2)= 5.085`
Percentage composition of `O_(2)= 54.22`
(ii) Vapour density of compound = 59
We are to find out the following
(a) Empirical formula and empirical formula mass
(b) Molecular formula and molecular formula mass.
Calculations
(i) Calculation of empirical formula and empirical formula mass.

So, empirical formula `= C_(20H_(3)O_(2)`
Empirical formula mass `=2 xx 12 +3 xx 1+ 2xx 16= 59`
(ii) Calculation of molecular formula and molecular formula mass We know that, Molecular formula mass `=2xx` varpour density `=2 xx 59= 118`
Using the relation `n= ("Molecular formula mass")/("Empirical formula mass") = (118)/(59)=2`
`therefore` Molecular formula `=2 xx (C_(2)H_(3)O_(2))= C_(4)H_(6)O_(4)`
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