Home
Class 11
CHEMISTRY
An organic compound has the following pe...

An organic compound has the following percentage composition : C= 48%, H= 8% N= 28% and rest of oxygen. Calculate the empirical formula of the compound.

Text Solution

Verified by Experts

We are given that
Percentage of carbon C= 48%
Percentage of hydrogen = 8%
Percentage of nitrogen = 28%
Percentage of oxygen = 16%
Calculation of empirical formula

`therefore` Empirical formula `=C_(4)H_(8)N_(2)O`
Promotional Banner

Topper's Solved these Questions

  • SOME BASIC CONCEPTS OF CHEMISTRY

    OMEGA PUBLICATION|Exercise Multiple Choice Questions (MCQs)|29 Videos
  • SAMPLE QUESTION PAPER -v (PUNJAB)

    OMEGA PUBLICATION|Exercise QUESTION|45 Videos
  • STATES OF MATTER

    OMEGA PUBLICATION|Exercise Multiple Choice Questions (MCQs) |29 Videos

Similar Questions

Explore conceptually related problems

An organic compound on analysis gave the following percentage composition of C= 57.8, H= 3.6 and the rest is oxygen. Vapour density of the compound is 83. Find out the molecular formula of the compound.

An inorganic salt gave the following percentage composition : Na= 29.11%, S= 40.51% and O= 30.38%. Calculate the empirical formula of the salt. (At. Mass Na= 23, S=32)

A substance on analysis gave the following percentage composition Na = 43.4% C = 11.3% O = 45.3% Calculate the empirical formula.

Calculate the percentage composition of C2H5OH.

A hydrocarbon contains 7.7 % hydrogen. calculate the empirical formula.

What is the simplest formula of the compound which has the following percentage composition carbon 80% , hydrogen 20% , if the molecular mass is 30. calculate its molecular formula ?

An inorganic substance on analysis gave the following results Na = 29.1% S = 40.5% and O = 30.4% . Calculate its empirical formula.

Write the empirical formulae of the compounds with the following percentage composition : Zn = 47.8% Cl = 52.2%

Determine the empirical formula of a compound with following percentage composition Cu= 47.3, Cl= 52.7.