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A solution is prepared by adding 60g of ...

A solution is prepared by adding 60g of methyl alcohol to 120g of water. calculate the mole fraction of methanol and water?

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We are given that Mass of methyl alcohol= 60g
Mass of water= 120g
We are to find out the mole fraction of methanol and water.
Moles of methyl alcohol `=(60)/(32)= 1.875` [Molar mass of `CH_(3)OH= 32`]
Moles of water= `(120)/(18)= 6.667` [Mass mass of `H_(2)O=18`]
Total number of moles `=1.875 + 6.667` = 8.542
So, mole fraction of methanol `=(1.875)/(8.542)= 0.220`
Mole fraction of water `=(6.667)/(8.542)= 0.780`
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Convert into moles : 20g of water