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How are 0.50mol Na(2)CO(3) and 0.50M Na(...

How are 0.50mol `Na_(2)CO_(3)` and 0.50M `Na_(2)CO_(3)` different?

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We have molar mass of `Na_(2)CO_(3)`
`Na_(2)CO_(3)= (2 xx 22.99) + 12.01 + (3 xx 6)= 105.99 ~~ 106 g mol^(-1)`
`therefore` 0.50 mole of `Na_(2) CO_(3)= 0.50 xx 106 = 53 g Na_(2)CO_(3)`
`0.50M Na_(2)CO_(3)` means 53g `Na_(2)CO_(3)` is present in 1L of the solution.
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