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Calculate the mass of sodium acetate (CH...

Calculate the mass of sodium acetate (CH3COONa) required to make 500 mL of 0.375 molar aqueous solution. Molar mass of sodium acetate is 82.0245 g mol–1

Text Solution

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Give, Molar mass of `CH_(3)COONa= 82.024g m^(-1)`
Molarity of solution = 0.357M = 0.357 mol `L^(-1)`
Volume of solution = 500mL `=(500)/(1000) = 0.5L`
Molarity of solution `=("Mass" CH_(3)COONa"/molar mass")/("Volume of solution in litres")`
`0.375 "mol" L^(-1)= (W)/((82.0245g mol^(-1)) xx (0.52))`
`W= (0.375 "mol" L^(-1)) xx (82.0245 g "mol"^(-1)) xx (0.52)= 15.375g`
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