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Find the energy of each of the photon wh...

Find the energy of each of the photon which have wavelength of 0.50 A*

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E = hv (According to Planck.s equntum equation)
`E = ( hc)/(lamda ) = ( because c = v lamda so, v = (c)/( lamda ))`
`E = ( 6.6 xx 10 ^(-34) Js xx 3 xx 10 ^(8) ms ^(-1))/( 0. 50 xx 10 ^(-10) m ) = 3. 98 xx 10 ^(-15) J`
`E = 3 98 xx 10 ^(-15) J`
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OMEGA PUBLICATION-STRUCTURE OF ATOM -MULTIPLE CHOICE QUESTIONS (MCQ s)
  1. Find the energy of each of the photon which have wavelength of 0.50 A*

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  2. Emission of beta -particle is equivatent to:

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  3. The mass of the neutron is of the order of

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  4. The number of electrons and neutrons of an element is 18 and 20 respec...

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  5. Which of the following has longest wavelength ?

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  6. The value of Planck's constant is

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  7. Which of the following expresson gives the de-Broglie relationship ?

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  8. The total number of orbitals possible for the quantum number n is

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  9. The four quantum numbers of the valence electron of potassium are

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  10. An electron has principal quantum number 3. The number of its (i) shel...

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  11. The correct set of quantum numbers for a 4d electron is

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  12. No two electrons in an atom will have all the four quantum numbers sam...

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  13. The correct order of increasing energy of atomic orbitals is

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  14. The energy of an electron in nth orbit of hydrogen atom is

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  15. The triad of nuclei that is isotonic is

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  16. Bohr's model can explain

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  17. If the value of l = 2, what will be the value of principal quantum num...

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  18. Rutherford's experiment on scattering of alpha particles showed for th...

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  19. 3d-orbitals have

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  20. Number of unpaired electrons in the electronic configuration 1s ^(2) ,...

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  21. The two electrons in an orbital have different

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