Home
Class 11
CHEMISTRY
State Heisenberg’s uncertainty principle...

State Heisenberg’s uncertainty principle.

Text Solution

Verified by Experts

Heisenberg.s uncertainty principle: It is not possible to measure simultaneously the exact position and exact momentum of a microscopic.particle.
Mathematical formula:`Delta x xx Delta p ge (h)/( 4pi )`
Where, `Delta x=` Uncertainty in position
`Delta p=` Uncertainty in momentum
`h, pi =` Constants
If `Delta x` is very small, `Delta p` will be quite large and vice-versa. So only one property is measured accurately at one time.
Promotional Banner

Topper's Solved these Questions

  • STRUCTURE OF ATOM

    OMEGA PUBLICATION|Exercise MULTIPLE CHOICE QUESTIONS (MCQ s) |29 Videos
  • STATES OF MATTER

    OMEGA PUBLICATION|Exercise Multiple Choice Questions (MCQs) |29 Videos
  • THE P-BLOCK ELEMENTS

    OMEGA PUBLICATION|Exercise MULTIPLE CHOICE QUESTIONS (MCQs)|28 Videos

Similar Questions

Explore conceptually related problems

Explain Heisenberg's uncertainty principle. Give its significance.

Werner Heisenberg considered the limits of how precisely we can measure the properties of an electron or other microscopic particle. He determined that there is a fundamental limit to how closely we can measure both position and momentum. The more accurately we measure the momentum of a particle, the less accurately we can determine its position. The converse also true. This is summed up in what we now call the Heisenberg uncertainty principle. The equation si deltax.delta (mv)ge(h)/(4pi) The uncertainty in the position or in the momentum of a marcroscopic object like a baseball is too small to observe. However, the mass of microscopic object such as an electon is small enough for the uncertainty to be relatively large and significant. If the uncertainties in position and momentum are equal, the uncertainty in the velocity is :

Werner Heisenberg considered the limits of how precisely we can measure the properties of an electron or other microscopic particle. He determined that there is a fundamental limit to how closely we can measure both position and momentum. The more accurately we measure the momentum of a particle, the less accurately we can determine its position. The converse also true. This is summed up in what we now call the Heisenberg uncertainty principle. The equation si deltax.delta (mv)ge(h)/(4pi) The uncertainty in the position or in the momentum of a marcroscopic object like a baseball is too small to observe. However, the mass of microscopic object such as an electon is small enough for the uncertainty to be relatively large and significant. If the uncertainty in velocity and position is same, then the uncertainty in momentum will be :

Werner Heisenberg considered the limits of how precisely we can measure the properties of an electron or other microscopic particle. He determined that there is a fundamental limit to how closely we can measure both position and momentum. The more accurately we measure the momentum of a particle, the less accurately we can determine its position. The converse also true. This is summed up in what we now call the Heisenberg uncertainty principle. The equation si deltax.delta (mv)ge(h)/(4pi) The uncertainty in the position or in the momentum of a marcroscopic object like a baseball is too small to observe. However, the mass of microscopic object such as an electon is small enough for the uncertainty to be relatively large and significant. What would be the minimum uncetaintty in de-Broglie wavelength of a moving electron accelerated by potential difference of 6 volt and whose uncetainty in position is (7)/(22) nm?

The Heisenberg uncertainty principle can be applied to:

Which of the following is the most correct expression for Heisenberg's uncertainity principle?

Assuming an electron is confined to a 1nm wide region. Find the uncertainty in momentum using Heisenberg Uncertainty principle. You can assume the uncertainty in position Deltax as 1nm. Assuming p=Deltap , find the energy of the electron in electron volts.

What is the significance of uncertainty principle ?

OMEGA PUBLICATION-STRUCTURE OF ATOM -MULTIPLE CHOICE QUESTIONS (MCQ s)
  1. State Heisenberg’s uncertainty principle.

    Text Solution

    |

  2. Emission of beta -particle is equivatent to:

    Text Solution

    |

  3. The mass of the neutron is of the order of

    Text Solution

    |

  4. The number of electrons and neutrons of an element is 18 and 20 respec...

    Text Solution

    |

  5. Which of the following has longest wavelength ?

    Text Solution

    |

  6. The value of Planck's constant is

    Text Solution

    |

  7. Which of the following expresson gives the de-Broglie relationship ?

    Text Solution

    |

  8. The total number of orbitals possible for the quantum number n is

    Text Solution

    |

  9. The four quantum numbers of the valence electron of potassium are

    Text Solution

    |

  10. An electron has principal quantum number 3. The number of its (i) shel...

    Text Solution

    |

  11. The correct set of quantum numbers for a 4d electron is

    Text Solution

    |

  12. No two electrons in an atom will have all the four quantum numbers sam...

    Text Solution

    |

  13. The correct order of increasing energy of atomic orbitals is

    Text Solution

    |

  14. The energy of an electron in nth orbit of hydrogen atom is

    Text Solution

    |

  15. The triad of nuclei that is isotonic is

    Text Solution

    |

  16. Bohr's model can explain

    Text Solution

    |

  17. If the value of l = 2, what will be the value of principal quantum num...

    Text Solution

    |

  18. Rutherford's experiment on scattering of alpha particles showed for th...

    Text Solution

    |

  19. 3d-orbitals have

    Text Solution

    |

  20. Number of unpaired electrons in the electronic configuration 1s ^(2) ,...

    Text Solution

    |

  21. The two electrons in an orbital have different

    Text Solution

    |