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20 mL of hydrogen measured at 15^(@)C is...

20 mL of hydrogen measured at `15^(@)C` is heated to `35^(@)C`. What is the new volume of gas at the same pressure ?

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We are given that
`V_(1) = 20 mL, T_(1) =15^(@)C and T_(2) =35^(@)C`
We are to find out the new volume of gas `(V_(2))`.
According to Charles. law
`(V_(1))/(T_(1)) =(V_(2))/(T_(2))` at constant pressure
`(20)/(15)= (V_(2))/(35)" " V_(2)=46.67mL`
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OMEGA PUBLICATION-STATES OF MATTER -Multiple Choice Questions (MCQs)
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