At `0^(@)C`, the density of certain oxide of a gas at 2 bar is same as that of dinitrogen at 5 bar. What is molecular mass of the oxide ?

Explanation

We are given that
`T=273^(@)K or 0^(@)C`
`p_(1)=2`
`p_(2)=5`
`m_(2)= 28`
d = density
We are in calculate the molecular mass of the oxide.
We know that, `d=(pM)/(RT)`
Density of oxide = density of dinitrogen
or `(p_(1)M_(1))/(RT)=(p_(2)M_(2))/(RT_(2))`
`2xxM_(1)=5 xx 28`
`M_(1)=70 g//"mol"`