A sample of nitrogen gas occupies a volume of 1.0L at a pressure of 0.5 bar and at 40∘C. Calculate the pressure the gas if compressed to 0.225ml at −6∘C

Explanation

`P_(1)=0.5 "bar " P_(2)=?`
`V_(1)=1.0L" " V_(2)=0.225 mL=0.225xx10^(-3)L`
`T_(1)=40C " " T_(2)=-6^(@)C`
`=273 +40 =313K" " T_(2)=273 -6=267K`
According to combined gas equation
`(P_(1)V_(1))/(T_(1))=(P_(2)V_(2))/(T_(2)), P_(2)=(P_(1)V_(1)T_(2))/(V_(2)T_(2))=(0.5 xx 1 xx 267)/(0.225xx10^(-3) xx 313)=1895.6 ` bar