A gascous mixture contains 56 g N_2, 44 g `CO_(2)` and 16 g `CH_(4)`. The total pressure of mixture is 720 mm. What is partial pressure of `CH_(4)`?

Explanation

We are given that
Number of moles of each gas.
i) 56g of `N_(2)` means 2 moles ii) 44g of `CO_(2)` means 1 mole iii) 16g of `CH_(4)` means 1 mole
Total pressure of mixture = 720 mm.
We are to find out the partial pressure of `CH_(4)`. As we know `P prop n`
Total number of moles `= 2+1 + 1 = 4`
Fraction of each gas `=(2)/(4)" of "N_(2), (1)/(4)" of " CH_(4) and (1)/(4) " of "CO_(2)`
Partial pressure of `CH_(4)=(1)/(4) xx 720 =180 mm`